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Subject: SAT 2008 - PHYSICS
Date: Thu, 15 May 2008 11:36:47 +0300
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<HTML><HEAD><TITLE>SAT 2008 - PHYSICS</TITLE>
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<DIV align=3Dcenter>
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<TABLE cellSpacing=3D0 cellPadding=3D0 width=3D"90%" border=3D0>
  <TBODY>
  <TR>
    <TD width=3D"100%"><B><FONT face=3DVerdana size=3D4>
      <P align=3Dcenter>PHYSICS</P>
      <DIV align=3Dcenter>
      <TABLE cellSpacing=3D0 cellPadding=3D0 width=3D"90%" border=3D0>
        <TBODY>
        <TR>
          <TD width=3D"50%"><B><FONT face=3DVerdana=20
            size=3D2>Time:&nbsp;ONE&nbsp;Hour</FONT></B></TD>
          <CENTER></CENTER>
          <TD width=3D"50%">
            <P align=3Dright><B><FONT face=3DVerdana=20
            =
size=3D2>Max.&nbsp;Marks:&nbsp;60</FONT></B></P></TD></TR></TBODY></TABLE=
></DIV></FONT>
      <CENTER><FONT face=3DVerdana size=3D2>
      <P align=3Djustify>&nbsp;</P>
      <DIV align=3Dcenter>
      <TABLE cellSpacing=3D0 cellPadding=3D0 width=3D"90%" border=3D0>
        <TBODY>
        <TR>
          <TD width=3D"100%">
            <UL><FONT face=3DVerdana size=3D2><I>
              <LI>
              <P align=3Dleft>Answers must be written either in English =
or the=20
              medium of instruction of the candidate in high school. =
</P>
              <LI>
              <P align=3Dleft>Answer all the questions in the booklets =
provided=20
              for the purpose. </P>
              <LI>
              <P align=3Dleft>There will be no negative marking. </P>
              <LI>
              <P align=3Dleft>The <B>relevant working or the argument in =
arriving=20
              at an answer has to be included </B></I><B>in your answer. =

              </B><I></P>
              <LI>
              <P align=3Dleft>Use of calculators or graph papers is not =
permitted.=20
              </P>
              <LI>
              <P align=3Dleft>Questions in <B>Part A</B> carry <B>6 =
marks</B> each=20
              and questions in <B>part B</B> carry <B>3 marks</B> each.=20
              =
</I></FONT></P></LI></UL></TD></TR></TBODY></TABLE></DIV></FONT></CENTER>=
</B>
      <UL><FONT face=3DVerdana size=3D2></UL></FONT>
      <CENTER><B><FONT size=3D2>
      <BLOCKQUOTE></FONT><FONT size=3D5>
        <P align=3Dcenter>Part A</P></FONT></B><FONT size=3D2>
        <P align=3Djustify></FONT><FONT size=3D4>1.Two liquids of masses =
600&nbsp;g=20
        and 500&nbsp;g and densities 0.6&nbsp;gcm<SUP>-3</SUP> and=20
        1.5&nbsp;gcm<SUP>-3</SUP> are combined to form a homogenous =
mixture. A=20
        solid block of mass 420&nbsp;g just floats in this mixture. Find =
the=20
        density of the block material. If the equal volumes of the two =
liquids=20
        were mixed instead, would this block float in that mixture? If =
it floats=20
        find the fraction of the block that is visible above the=20
        mixture.</P></FONT><FONT size=3D2>
        <P align=3Djustify></FONT><FONT size=3D4>2.A lens of focal =
length f produces=20
        an image of an object located 30 cm on one side of it at a =
distance of=20
        60 cm on the other side. If the lens is replaced by another of =
3f/4,=20
        where would the image form? If the image has to form at the =
earlier=20
        position by what distance should the object be =
shifted?</P></FONT><FONT=20
        size=3D2>
        <P align=3Djustify></FONT><FONT size=3D4>3.The devices =
D<SUB>1</SUB> and=20
        D<SUB>2</SUB> shown (below left) are called diodes and have an=20
        interesting property. When current flows in the direction of the =
arrow=20
        the resistance is low and is called forward bias resistance. If =
the=20
        current were to flow in the opposite direction the resistance is =
high=20
        and it is called reverse bias resistance. For D<SUB>1</SUB> =
forward bias=20
        resistance is 20 Ohm and reverse bias resistance is 600 Ohm. For =

        D<SUB>2</SUB> forward bias resistance is 30 Ohm and reverse bias =

        resistance is 200 Ohm. Find the equivalent resistance between A =
and B if=20
        (i) A is at a higher potential (ii) B is at a higher=20
        potential</P></FONT><FONT size=3D2>
        <P align=3Dleft></FONT><FONT size=3D4>4.Rays of light are =
incident=20
        symmetrically on a sphere of radius R as shown (below middle). =
Determine=20
        the refractive index of the sphere material if they meet at P =
(You need=20
        to write the correct expression for refractive index). Can the =
rays be=20
        made to meet at C, the center of the sphere. If not, how should =
the rays=20
        be incident to meet at C.</P></BLOCKQUOTE></FONT>
      <TABLE cellSpacing=3D0 cellPadding=3D0 width=3D"100%" border=3D0>
        <TBODY>
        <TR>
          <TD vAlign=3Dtop width=3D"34%"><FONT size=3D4>
            <P align=3Dright><IMG height=3D201=20
            =
src=3D"http://surendranath.tripod.com/Sat/Sat08/Phy/Image115.gif"=20
            width=3D361></FONT></P></TD>
          <TD vAlign=3Dtop width=3D"34%"><FONT size=3D4>
            <P align=3Dright><IMG height=3D201=20
            =
src=3D"http://surendranath.tripod.com/Sat/Sat08/Phy/Image116.gif"=20
            width=3D313></FONT></P></TD>
          <TD vAlign=3Dtop width=3D"32%"><FONT size=3D4>
            <P align=3Dcenter><IMG height=3D201=20
            =
src=3D"http://surendranath.tripod.com/Sat/Sat08/Phy/Image117.gif"=20
            width=3D313></FONT></P></TD></TR></TBODY></TABLE>
      <BLOCKQUOTE><FONT size=3D2>
        <P align=3Djustify></FONT><FONT size=3D4>5.If the measured =
potential=20
        difference between A and B is 5.4&nbsp;V, Find the rate of heat=20
        production in the ring (above right). Also find the rate of heat =

        production in sections ACB and =
ADB.</P></FONT><B></BLOCKQUOTE></B>
      <TABLE cellSpacing=3D0 cellPadding=3D0 width=3D1016 border=3D0>
        <TBODY>
        <TR>
          <TD vAlign=3Dtop width=3D561>
            <BLOCKQUOTE><FONT size=3D2>
              <P align=3Djustify></FONT><FONT size=3D4>6.Two identical =
rectangular=20
              tanks are connected by a small tube at the bottom. In the =
left=20
              tank contains liquid of density=20
              d<SUB>1</SUB>=3D800&nbsp;kg/m<SUP>3</SUP> to a height=20
              <I>h</I><SUB>1</SUB>=3D30&nbsp;cm. The right tank contains =
liquid of=20
              density d<SUB>2</SUB>=3D1600&nbsp;kg/m<SUP>3</SUP>, to a =
height=20
              <I>h</I><SUB>2</SUB>=3D20&nbsp;cm. The two liquids don't =
mix. a)=20
              Find the heights of the respective columns, if a small =
tube=20
              connects them at the bottom. b) Where should a horizontal =
tube be=20
              connected, without causing any flow between the tanks?=20
            </P></BLOCKQUOTE></FONT></TD>
          <TD vAlign=3Dcenter width=3D451>
            <BLOCKQUOTE><FONT size=3D4>
              <P align=3Dcenter><IMG height=3D186=20
              =
src=3D"http://surendranath.tripod.com/Sat/Sat08/Phy/Image118.gif"=20
              width=3D325> =
</P></BLOCKQUOTE></FONT></TD></TR></TBODY></TABLE>
      <BLOCKQUOTE><B><FONT size=3D5>
        <P align=3Dcenter>Part B</P></FONT></B><FONT size=3D2>
        <P align=3Djustify></FONT><FONT size=3D4>7.Two candles of =
identical lengths=20
        and different thicknesses were lit. Half of the thin candle and =
one=20
        third of the thick candle could be seen to burn down in 15 =
minutes. How=20
        long after the candles had been lit was the ratio of their =
lengths=20
        4.</P></FONT><FONT size=3D2>
        <P align=3Djustify></FONT><FONT size=3D4>8.The average daily =
loss of water=20
        of a human body is 0.8&nbsp;kg, evaporated by the body. How much =
food=20
        has to be consumed in order to compensate for the loss of energy =
due to=20
        the evaporation if human body can use 70% of the energy provided =
by the=20
        decomposition of food. The heat of combustion of food is=20
        6,000&nbsp;kJ/kg, the heat of vaporisation of water is=20
        2440&nbsp;kJ/kg</P></FONT><FONT size=3D2>
        <P align=3Djustify></FONT><FONT size=3D4>9.A train of length =
300&nbsp;m=20
        passes through two tunnels with a gap of 400&nbsp;m between them =
.The=20
        tunnels are of length 800&nbsp;m and 600&nbsp;m respectively. =
From the=20
        moment it just emerges from the first tunnel to the moment it =
just=20
        disappears in to the second tunnel time elapsed is 60&nbsp;s. =
Find the=20
        time elapsed between the moments the train just enters the first =
tunnel=20
        to the moment it just leaves the second tunnel.</P></FONT><FONT =
size=3D2>
        <P align=3Djustify></FONT><FONT size=3D4>10.Fiber optic cable of =
length L=20
        has an inner core surrounded by an outer jacket. Light can =
travel along=20
        the length of the cable through the inner and outer portions. =
The=20
        refractive indices of the material of the inner and outer =
portions are=20
        <FONT face=3DSymbol>m</FONT> <SUB>1</SUB> and <FONT =
face=3DSymbol>m</FONT>=20
        <SUB>2</SUB>. Find the time interval between the moments when a =
light=20
        pulse entering one end of the cable arrives at the other end =
traveling=20
        through the inner and outer portions.</P></FONT><FONT size=3D2>
        <P align=3Dleft></FONT><FONT size=3D4>11.A person's heart does =
approximately=20
        a work of 1.6&nbsp;J during a beat. How much work does it do =
during a=20
        day? By how much does the temperature of 10 kg of water rise if =
it=20
        absorbs this much of energy?</P></FONT>
        <P align=3Djustify>12.Find <FONT size=3D4>the ratio=20
        E<SUB>i</SUB>/E<SUB>f</SUB>, where E<SUB>i</SUB> and =
E<SUB>f</SUB> are=20
        the energies of a neutron before and after interaction with the =
nuclei=20
        of the moderator in a nuclear reactor.</P></FONT><FONT size=3D2>
        <P align=3Djustify></FONT><FONT size=3D4>13.A stone projected =
vertically=20
        upward on some planet reaches a maximum height h. Find the ratio =
of=20
        times after projection when it is at a height of =
5h/9.</P></FONT><FONT=20
        size=3D2>
        <P align=3Djustify></FONT><FONT size=3D4>14.A horizontal =
conductor is=20
        oriented north south and carries some current. A positively =
charged=20
        particle located vertically above it and having a velocity =
directed=20
        northward experiences an upward force. What is the direction of =
the=20
        force if this charged particle were located to the east of the =
conductor=20
        and had a velocity directed towards the =
conductor.</P></BLOCKQUOTE></FONT>
      =
<P>&nbsp;</P></CENTER></TD></TR></TBODY></TABLE></CENTER></DIV></BODY></H=
TML>

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